y^2=2y+80

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Solution for y^2=2y+80 equation:


Simplifying
y2 = 2y + 80

Reorder the terms:
y2 = 80 + 2y

Solving
y2 = 80 + 2y

Solving for variable 'y'.

Reorder the terms:
-80 + -2y + y2 = 80 + 2y + -80 + -2y

Reorder the terms:
-80 + -2y + y2 = 80 + -80 + 2y + -2y

Combine like terms: 80 + -80 = 0
-80 + -2y + y2 = 0 + 2y + -2y
-80 + -2y + y2 = 2y + -2y

Combine like terms: 2y + -2y = 0
-80 + -2y + y2 = 0

Factor a trinomial.
(-8 + -1y)(10 + -1y) = 0

Subproblem 1

Set the factor '(-8 + -1y)' equal to zero and attempt to solve: Simplifying -8 + -1y = 0 Solving -8 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '8' to each side of the equation. -8 + 8 + -1y = 0 + 8 Combine like terms: -8 + 8 = 0 0 + -1y = 0 + 8 -1y = 0 + 8 Combine like terms: 0 + 8 = 8 -1y = 8 Divide each side by '-1'. y = -8 Simplifying y = -8

Subproblem 2

Set the factor '(10 + -1y)' equal to zero and attempt to solve: Simplifying 10 + -1y = 0 Solving 10 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -1y = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -1y = 0 + -10 -1y = 0 + -10 Combine like terms: 0 + -10 = -10 -1y = -10 Divide each side by '-1'. y = 10 Simplifying y = 10

Solution

y = {-8, 10}

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